Step 1: Find valence e- for all atoms. Add them together.
Step2: Find octet e- for each atom and add them together.
*Xe should get 10 electrons for its octet so that it can form 2 bonds with side atoms.
Step3: Gives you bonding e-. Subtract step 1 total from step 2
Step 4: Find number of bonds by diving the number in step 3 by 2(because each bond is made of 2 e-)
4e-/2= 2 bond pairs
Step 5: Find the number of nonbonding (lone pairs) e-. Subtract step 3 number from step 1.
22-4= 18e-=9 lone pairs
Use information from step 4 and 5 to draw the lewis structure.
Lewis dot structure of Xef2
Alternatively a dot method can be used to draw the lewis structure.
Calculate the total valence electrons in the molecule.
Put Xenon in center and arrange chlorine atoms on the sides.Arrange electrons until fluorine atoms get 8 electrons.( Xenon gets 10 electrons, which is an expanded octet)